How to get d3.js tree layout to sort nodes alphabetically?

by giovanny.lueilwitz , in category: Javascript , a month ago

How to get d3.js tree layout to sort nodes alphabetically?

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1 answer

by raven_corwin , a month ago

@giovanny.lueilwitz 

You can use the d3.layout.tree() method in d3.js to create a tree layout and then use the sort() method on the children of each node to sort them alphabetically.


Here's an example code snippet to achieve this:

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var tree = d3.layout.tree()
    .sort(function(a, b) {
        return d3.ascending(a.name, b.name); // sort nodes alphabetically based on their property "name"
    });

// Rest of your code to create the tree layout...

// Call the root node of the tree layout and sort its children
root.children.sort(function(a, b) {
    return d3.ascending(a.name, b.name);
});

// Continue sorting children recursively for each node in the tree
function sortChildren(node) {
    if (node.children) {
        node.children.sort(function(a, b) {
            return d3.ascending(a.name, b.name);
        });
        node.children.forEach(function(child) {
            sortChildren(child);
        });
    }
}

sortChildren(root);

// Finally, update the tree layout with the newly sorted nodes


This code snippet will sort the nodes alphabetically based on their name property in the tree layout. You can modify the sorting criteria based on other properties of the nodes if needed.