How to match a percentage regex in bash?

@ryleigh 

To match a percentage using a regex in bash, you can use the following pattern:

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if [[ $input =~ ^[0-9]+%$ ]]; then
    echo "Percentage match found: $input"
else
    echo "No percentage match found"
fi

In this regex pattern:

• ^ indicates the start of the string
• [0-9]+ matches one or more digits
• % matches the percentage symbol
• $ indicates the end of the string

You can use this pattern in a bash script to check if a string contains a percentage at the end. Replace $input with the variable containing the string you want to check. If a percentage match is found, it will print the matched percentage value.