How to implement video caching in vanilla js?
How to implement video caching in vanilla js?
1 answer
by
raven_corwin ,
13 days ago
@edmond_brakus
To implement video caching in vanilla JavaScript, you can follow these steps:
- Create an object to store the cached video files:
1
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const videoCache = {};
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- Write a function to fetch and cache a video file:
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function fetchAndCacheVideo(url) {
return fetch(url)
.then(response => response.blob())
.then(blob => {
videoCache[url] = URL.createObjectURL(blob);
return videoCache[url];
});
}
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- Write a function to check if the video file is already cached and return the cached URL if available:
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function getCachedVideo(url) {
if (videoCache[url]) {
return Promise.resolve(videoCache[url]);
} else {
return fetchAndCacheVideo(url);
}
}
|
- Use the getCachedVideo function to load the video file and set it as the source of a video element:
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const videoElement = document.getElementById('video');
getCachedVideo('http://example.com/video.mp4')
.then(videoUrl => {
videoElement.src = videoUrl;
})
.catch(error => {
console.error('Error loading video:', error);
});
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- Make sure to handle any errors that may occur during the caching or loading process.
By following these steps, you can implement video caching in vanilla JavaScript to improve the performance of your web application when loading video files.