How to create a logout function in Symfony?

by scotty_walker , in category: PHP Frameworks , 15 days ago

How to create a logout function in Symfony?

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1 answer

by lindsey.homenick , 6 hours ago

@scotty_walker 

To create a logout function in Symfony, you can follow these steps:

  1. Define a new route for logout in your routes.yaml file:
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logout:
    path: /logout


  1. Create a new controller method to handle the logout request:
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namespace AppController;

use SymfonyComponentHttpFoundationResponse;
use SymfonyComponentRoutingAnnotationRoute;
use SymfonyComponentSecurityHttpLogoutLogoutSuccessHandlerInterface;

class SecurityController extends AbstractController
{
    /**
     * @Route("/logout", name="app_logout")
     */
    public function logout(LogoutSuccessHandlerInterface $logoutSuccessHandler): Response
    {
        return $logoutSuccessHandler->onLogoutSuccess();
    }
}


  1. Configure the logout path in your security.yaml file:
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security:
    # ...
    logout:
        path: app_logout
        target: app_homepage # optional - redirect target after logout


  1. Use the logout_path function in your templates to generate the logout URL:
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<a href="{{ logout_path('app_logout') }}">Logout</a>


This should create a functional logout function in Symfony. When the user clicks on the logout link, Symfony will invalidate their session and redirect them to the configured logout target.